How much torque must the pin exert to keep the rod from rotating?

In summary, the problem is asking for the torque that the pin must exert at the point of rotation to keep the rod from rotating. The equation used is \Sigma\taunet=0=\taupin-\tauM-\taum, and the attempt at a solution involved using the mass instead of the force and forgetting to multiply by the acceleration constant g.
  • #1
nweis84
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Homework Statement



How much torque must the pin exert to keep the rod from rotating?
(L=1.011m , M=3kg , m = .301kg)

So I am guessing the point of rotation is the pin??
But then how does the pin exert any torque if it is at the point of rotation?
I'm not quite sure


there is a sketch I've attached

Homework Equations



Ive used the equation [tex]\Sigma[/tex][tex]\tau[/tex]net=0=[tex]\tau[/tex]pin-[tex]\tau[/tex]M-[tex]\tau[/tex]m

The Attempt at a Solution


i have tried it so many ways and keep getting it wrong

[tex]\tau[/tex]pin = 3kg*(1.011m/2) + .301kg*1.011m
what am i doing wrong?
Please help thankyou
 

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  • #2


For this type of problem, you probably don't need to worry about how the pin exerts a torque (though you can imagine in reality it would take a fair amount of force since there is only a small lever arm)

It looks like you've neglected to calculate the force of each of the masses and are using the mass instead (kg*m is not the units of force)
 
  • #3


yeah thank you i did forget to multiply by the acceleration constant g
 

FAQ: How much torque must the pin exert to keep the rod from rotating?

1. What is torque?

Torque is a measure of the force that causes an object to rotate around an axis. It is the product of the force applied and the distance from the axis to the point of application.

2. How is torque calculated?

Torque is calculated by multiplying the force applied by the distance from the axis to the point of application. The formula for torque is T = F x d, where T is torque, F is force, and d is distance.

3. What units is torque measured in?

Torque is typically measured in newton-meters (N⋅m) or foot-pounds (ft⋅lb).

4. How does torque affect rotational motion?

Torque is directly proportional to an object's rotational acceleration. This means that the greater the torque, the faster an object will rotate around an axis.

5. How much torque is needed to keep a rod from rotating?

The amount of torque needed to keep a rod from rotating depends on the length of the rod, the weight of the object at the end of the rod, and the force of gravity acting on the object. The formula for calculating this torque is T = m x g x L, where T is torque, m is the mass of the object, g is the acceleration due to gravity, and L is the length of the rod.

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