How Much Work Does the Landing Mat Perform on Yelena Isinbayeva?

In summary: I was supposed to do. I was supposed to find the work the mat did on her, not the work she did on the mat. Sorry.In summary, the pole vaulter Yelena Isinbayeva, weighing 60.1 kg, is at a point in her vault where the pole is maximally deflected (Δx = 1.60 m). The pole has a bending stiffness of 1000 N/m and behaves according to Hooke's Law. At this point, her vertical velocity is 4.18 m/s and she is 2.41 m above the ground. Assuming she lands on a mat with a top surface 1 m above the ground and
  • #1
x2017
84
1

Homework Statement


Pole vaulter Yelena Isinbayeva (64.1 kg) is at a point in her vault where the pole is maximally deflected (Δx = 1.63 m). The pole has a bending stiffness of 1091 N/m and behaves according to Hooke's Law. At this point in the vault, her vertical velocity is 3.25 m/s and she is 2.48 m above the ground.

Assume the vaulter lands on a mat whose top surface is 1 m above the ground and that the mat deforms by 0.5 m in bringing the vaulter to a complete stop. How much work was done on the vaulter by the mat?

Homework Equations


P=W/t
work done = change in energy
Hooke's Law: Fs=kΔx
Ws=(1/2)kΔx2
KE=(1/2)mv2
PEg=mgh
SE=(1/2)kΔx2
Total energy = KE+PE+SE
W=FΔd

I have already calculated the following from previous questions
Work done on the pole = 1449.34J
SE stored in the pole = 1449.34J
Force applied to the pole = 1778.33N
KE in vertical direction = 338.53J
PEg = 1559.48J
Peak height of her centre of mass = 5.32m
Work done by gravity from 2.48m above ground to peak height = -1785.80J
Time it took to fall from peak height to mat = 0.94s
The vertical velocity she first contacted the mat at = -9.21m/s

The Attempt at a Solution


My attempts are all giving me the same number so I'm pretty sure I'm thinking about it or interpreting it in an incorrect way.

I tried
W=FΔd
W=[(64.1)(9.81)](1+0.5)
W=943.23

PEg=mgh
PEg=(64.)(9.81)(1.5)
PEg=-943.23

Tried it negative the second time just to see...
 
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  • #2
In all those numbers, which is your final answer?
You do not need to find the height of the vault, or the speed on hitting the mat. Just consider the total energy at the instant described and the total energy at the end. Where has the difference gone?
I do notice what looks like a distance of 1.5m in your calculation. Where is that coming from?
 
  • #3
haruspex said:
In all those numbers, which is your final answer?
You do not need to find the height of the vault, or the speed on hitting the mat. Just consider the total energy at the instant described and the total energy at the end. Where has the difference gone?
I do notice what looks like a distance of 1.5m in your calculation. Where is that coming from?

My final answer was 943.23J.

The 1.5m distance is the mat's distance from the ground + how far the mat sinks down (0.5m)
 
  • #4
haruspex said:
In all those numbers, which is your final answer?
You do not need to find the height of the vault, or the speed on hitting the mat. Just consider the total energy at the instant described and the total energy at the end. Where has the difference gone?
I do notice what looks like a distance of 1.5m in your calculation. Where is that coming from?

Thinking about what you said about total energy I thought maybe this might work:
W=KEf-KEi
W=(1/2)mv2-(1/2)mv2
W=(1/2)(64.1)(0)2-(1/2)(64.1)(-9.21)2
W=0-2718.61
W=-2718.61J

This turned out to also be incorrect.
 
  • #5
x2017 said:
My final answer was 943.23J.

The 1.5m distance is the mat's distance from the ground + how far the mat sinks down (0.5m)
The surface of the mat starts 1m off the ground. When depressed .5m by the athlete, how far is it off the ground?
 
  • #6
haruspex said:
The surface of the mat starts 1m off the ground. When depressed .5m by the athlete, how far is it off the ground?
Ohhhhhhh my goodness 0.5m! Can't believe I overlooked that, I even have it drawn out on my paper... :oops:

W=FΔd
W=[(64.1)(9.81)](0.5)
W=314.41J

This is not correct when I put it into my assignment either

I don't understand. I thought that the work required to stop a falling object was the KE, which I tried above and was not correct.
 
  • #7
x2017 said:
Ohhhhhhh my goodness 0.5m! Can't believe I overlooked that, I even have it drawn out on my paper... :oops:

W=FΔd
W=[(64.1)(9.81)](0.5)
W=314.41J

This is not correct when I put it into my assignment either

I don't understand. I thought that the work required to stop a falling object was the KE, which I tried above and was not correct.
Yes, you have to take all the energy into account. All that was wrong with your previous attempt (I think) is you had the wrong final height from the ground.
Go back to your first post where you calculated all the energies at the given initial instant. Figure out the final total energy (i.e. at a height of 0.5m), and calculate the lost energy.
 
  • #8
haruspex said:
Yes, you have to take all the energy into account. All that was wrong with your previous attempt (I think) is you had the wrong final height from the ground.
Go back to your first post where you calculated all the energies at the given initial instant. Figure out the final total energy (i.e. at a height of 0.5m), and calculate the lost energy.
Okay,

TE=PEg+SE+KE
TE=1559.48+1449.34+338.53
TE=3008.82

But make it -3008.82 because it is opposite the direction Yelena is travelling.
My online assignment told me this is correct. Thank you for your help! :)
 
  • #9
x2017 said:
Okay,

TE=PEg+SE+KE
TE=1559.48+1449.34+338.53
TE=3008.82

But make it -3008.82 because it is opposite the direction Yelena is travelling.
My online assignment told me this is correct. Thank you for your help! :)
Ok!
 
  • #10
How did you get 3008.82 for total energy when I did it I got 3347.35
 
  • #11
Jthoms said:
How did you get 3008.82 for total energy when I did it I got 3347.35
I assume x2017's last post left out part of the working. As noted in the thread, the remaining PE (0.5m above ground) needs to be subtracted from the energy absorbed. That doesn't quite seem to fix up the discrepancy, but it's close. If you are still bothered, please post your working.
 
  • #12
The above image shows Yelena Isinbayeva (60.1 kg) at a point in her vault where the pole is maximally deflected (Δx = 1.60 m). The pole has a bending stiffness of 1000 N/m and behaves according to Hooke's Law. At this point in the vault, her vertical velocity is 4.18 m/s and she is 2.41 m above the ground.

Assume the vaulter lands on a mat whose top surface is 1 m above the ground and that the mat deforms by 0.5 m in bringing the vaulter to a complete stop. How much work was done on the vaulter by the mat?
I had the same question but different numbers.
For PE I got 1420.9
KE=525.04
SE= 1280
so I did the same thing for TE=1420.9+1280+525.04=3226
It wasn't the right answer so I don't know what I'm doing wrong.
 
  • #13
Jthoms said:
The above image shows Yelena Isinbayeva (60.1 kg) at a point in her vault where the pole is maximally deflected (Δx = 1.60 m). The pole has a bending stiffness of 1000 N/m and behaves according to Hooke's Law. At this point in the vault, her vertical velocity is 4.18 m/s and she is 2.41 m above the ground.

Assume the vaulter lands on a mat whose top surface is 1 m above the ground and that the mat deforms by 0.5 m in bringing the vaulter to a complete stop. How much work was done on the vaulter by the mat?
I had the same question but different numbers.
For PE I got 1420.9
KE=525.04
SE= 1280
so I did the same thing for TE=1420.9+1280+525.04=3226
It wasn't the right answer so I don't know what I'm doing wrong.
At what height does she come to rest?
 
  • #14
Her peak height is 5.47 m and she lands on the mat and is depressed by 0.5m
 
  • #15
Jthoms said:
Her peak height is 5.47 m and she lands on the mat and is depressed by 0.5m
In this way of solving the problem (comparing total energy at the described instant with total energy at the end) the peak height is irrelevant.
I asked what height she is off the ground at the end.
 
  • #16
the mat is 1m above the ground and she depresses it to 0.5m so I guess she would be 0.5 m off the ground, its the same question as the above one but with different numbers.
 
  • #17
Jthoms said:
the mat is 1m above the ground and she depresses it to 0.5m so I guess she would be 0.5 m off the ground.
yes. Did you take that into account in your energy calculation?
 
  • #18
I'm not sure how you would take in into account, how would you go about doing that?
 
  • #19
Jthoms said:
I'm not sure how you would take in into account, how would you go about doing that?
How did you calculate the PE in post #12?
 
  • #20
Never mind I got it, thanks for the help.
 
  • #21
Jthoms said:
How did you get 3008.82 for total energy when I did it I got 3347.35

haruspex said:
I assume x2017's last post left out part of the working. As noted in the thread, the remaining PE (0.5m above ground) needs to be subtracted from the energy absorbed. That doesn't quite seem to fix up the discrepancy, but it's close. If you are still bothered, please post your working.

Yeah, I didn't add the KE in, just SE & PE sorry about that!
The way I did it wouldn't work for my roommate, which makes me think I just got lucky... Did adding up energies work for you?
 
  • #22
I did peak height minus 0.5 so 5.47-0.5=4.97 then I did the PE=mgh using that new height and I got it
 
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FAQ: How Much Work Does the Landing Mat Perform on Yelena Isinbayeva?

What is the purpose of a landing mat?

A landing mat is a specialized type of surface that is designed to provide a safe and cushioned landing for people or objects. It is commonly used in sports and military training activities, as well as in emergency situations.

How does a landing mat work?

A landing mat typically consists of multiple layers of foam, rubber, or other shock-absorbing materials. These layers are designed to compress and absorb the impact of a landing, reducing the force and potential for injury. The mat may also have a non-slip surface to help prevent falls.

What are the benefits of using a landing mat?

The main benefit of using a landing mat is to protect individuals from injury during high-impact activities. By absorbing the force of a landing, a landing mat can reduce the risk of sprains, strains, and other injuries. It can also provide a more comfortable surface for training and improve overall performance.

What factors should be considered when choosing a landing mat?

When choosing a landing mat, it is important to consider factors such as the type of activity it will be used for, the size and weight of the individuals using it, and the level of impact it needs to absorb. The durability and quality of the materials used in the mat should also be taken into account.

Are there any safety precautions to keep in mind when using a landing mat?

Yes, there are some important safety precautions to keep in mind when using a landing mat. It is important to properly secure the mat to the ground to prevent it from moving or sliding during use. Users should also be trained on how to land safely on the mat to avoid injury. Regular inspections and maintenance of the mat are also recommended to ensure its effectiveness and safety.

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