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Homework Statement
A 60 kg load is raised by a two-pulley arrangement. How much work is done by the
force F to raise the load 3 m if there is a frictional force of 20 N in each pulley? Note that the pulleys do
not rotate, but the rope slides across each surface.
I've solved the problem, I would like to know if my answer is right. Otherwise, could you please tell me where I did wrong. thanks guys!
Homework Equations
F=mg
W=F*d
The Attempt at a Solution
m = 60kg
F(friction) = 20N
d = 3mF=mg∕2 + 2F(friction) = (60kg×9.8m/s²)/2 + 2×20N = 334N
W=F×2d= 334N ×2 × 3m = 2004 J
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