- #1
chukie
- 80
- 0
Human tissue contains about 3*10^27 electrons per kg of material. Suppose two humans are located 1370 km apart and each has a mass of 60 kg. We now transfer 5*10^21 electrons from one person to the other. What will be the magnitude of the resulting attraction, rounded to the nearest Newton?
I used the equation F=kQ1Q2/r^2
except I am not sure if I used the right charges.
for Q1, i found it by ((3*10^27)(6)-(5*10^21))(1.6*10^-19)
and Q2: ((3*10^27)(6)+(5*10^21))(1.6*10^-19)
I used the equation F=kQ1Q2/r^2
except I am not sure if I used the right charges.
for Q1, i found it by ((3*10^27)(6)-(5*10^21))(1.6*10^-19)
and Q2: ((3*10^27)(6)+(5*10^21))(1.6*10^-19)