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LuGoBi
Have you guys noticed how the acceleration of gravity is almost equal to pi squared?
nicksauce said:Hm? g is 175.55 furlongs/minute^2. How is that almost equal to pi^2? Or does it only work in some arbitrarily selected set of units?
cristo said:mgb_phys has answered that.
nicksauce said:Yes, I know. I just thought a hard example like that might help show the OP how absurd this sort of numerology is.
The acceleration of gravity is the rate at which an object falls towards the Earth due to the force of gravity. It is approximately 9.8 meters per second squared (m/s²) on the surface of the Earth.
The acceleration of gravity is calculated using the formula: a = F/m, where "a" represents acceleration, "F" represents force, and "m" represents mass. In the case of gravity, the force is the gravitational force exerted by the Earth on an object with a certain mass, causing it to accelerate towards the Earth.
The number pi (π) represents the ratio of a circle's circumference to its diameter, and when squared, it represents the area of a circle. In the case of the acceleration of gravity, pi squared (π²) is used in the formula for calculating the gravitational force between two objects: F = G(m1m2)/r², where "F" is the force of gravity, "G" is the gravitational constant, "m1" and "m2" are the masses of the two objects, and "r" is the distance between them.
The acceleration of gravity is almost equal to pi squared because it is derived from the gravitational force formula, which includes the gravitational constant and the distance between two objects. The value of pi squared is a constant, and the Earth's gravitational constant is also a constant, making the acceleration of gravity almost equal to pi squared.
No, the acceleration of gravity cannot be exactly equal to pi squared because it is a physical quantity that is affected by various factors such as the mass and distance of two objects. While it may be close to pi squared, it will never be exactly equal to it.