- #1
Yankel
- 395
- 0
Hello all,
Please look at the following:
Solve the equation:
\[\left | z \right |i+2z=\sqrt{3}\]
where z is a complex number.
I tried solving it, and did the following, which is for some reason wrong. I saw a correct solution. My question to you is why mine is not, i.e., where is my mistake ?
\[i\sqrt{x^{2}+y^{2}}+(2x+2iy)=\sqrt{3}\]
\[(x^{2}+y^{2})(-1)+(4x^{2}+8xiy-4y^{2})=3\]
\[3x^{2}-5y^{2}+8xiy=3\]
\[(1,0),(-1,0)\]
This is definitely wrong. Can you please tell me where my mistake it ?
Thank you !
The correct answer should be: \[\frac{\sqrt{3}}{2}-\frac{1}{2}i\]
Please look at the following:
Solve the equation:
\[\left | z \right |i+2z=\sqrt{3}\]
where z is a complex number.
I tried solving it, and did the following, which is for some reason wrong. I saw a correct solution. My question to you is why mine is not, i.e., where is my mistake ?
\[i\sqrt{x^{2}+y^{2}}+(2x+2iy)=\sqrt{3}\]
\[(x^{2}+y^{2})(-1)+(4x^{2}+8xiy-4y^{2})=3\]
\[3x^{2}-5y^{2}+8xiy=3\]
\[(1,0),(-1,0)\]
This is definitely wrong. Can you please tell me where my mistake it ?
Thank you !
The correct answer should be: \[\frac{\sqrt{3}}{2}-\frac{1}{2}i\]