How to Calculate Constant Acceleration and Distance?

[Masq]

Homework Statement

Q1: A car accelerates uniformly from rest to a
speed of 79.7 mi/h in 9.01 s.
Find the constant acceleration (expressed
in m/s2) of the car. Answer in units of m/s2.


Q2: Find the distance (expressed in m) that the
car travels during this time. Answer in units
of m.

Homework Equations

Acceleration
Distance

The Attempt at a Solution

Q1:
79.7mi/h = 35.6m/s
35.6/9.01 = 3.95m/s2

Q2:
3.95/2 * 9.01 = 17.79m

 

[Rake-MC]

Q1 looks fine to me, Q2 though, what formulae did you use?

I would have used $$s = ut + \frac{1}{2} at^2$$

where s = displacement
u = initial velocity
t = time
a = acceleration

This is the same as what you've done except your t is not squared.

 

[baba89]

I can confirm that your calculations are correct. The constant acceleration of the car is 3.95 m/s2 and the distance it travels during the given time is 17.79 meters. This information can be useful in understanding the motion of the car and can be used to make predictions about its future motion. It also highlights the importance of units and conversions in scientific calculations.