- #1
zenterix
- 708
- 84
- Homework Statement
- When dealing with differential vectors, I still struggle sometimes.
I'd like to calculate the differential of work done by a force acting on a particle mass undergoing circular motion
- Relevant Equations
- Let ##\vec{r}## be the vector from the center of the circular motion to the particle.
I believe I can write the equation below, but I am not sure if it is an equality or an approximation.
$$d\vec{r}=\vec{r} \times d\vec{\theta}$$
$$dW=\vec{F} \cdot d\vec{r}$$
$$=\vec{F} \cdot (\vec{r} \times d\vec{\theta})$$
$$=(\vec{F} \times \vec{r})\cdot d\vec{\theta}$$
$$=-(\vec{r} \times \vec{F})\cdot d\vec{\theta}$$
$$\implies dW=-\vec{\tau} \cdot d\vec{\theta}$$
My question is, is this correct, and if so, why the minus sign?