- #1
roam
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Homework Statement
This is about experimental physics. I have a value of resistance [tex]R=9000 \pm 1000[/tex]. Then I had to do the following calculation:
[tex]\frac{40000}{9000}=4.44 \ \Omega[/tex]
So, I'm not quite sure how to calculate the final uncertainty from my uncertainty [tex]\sigma = \pm 1 \ k\Omega[/tex]
The Attempt at a Solution
Since [tex]9000 \times (4.8 \times 10^{-4}) = 4.44[/tex]
I used the rule that says [tex]y=na \implies \sigma_{y}=n \sigma_a[/tex]
so:
[tex]\sigma = 1000 \times (4.8 \times 10^{-4}) = 0.48 \ \Omega[/tex].
Is this correct? Would the final uncertainty be ±0.48?