Speaking of grains of salt,
can anybody please tell me the formula for heat rate for fuels?Dx said:A heat engine has efficiency of 30% and its power is 600W. what is the rate of heat input?
is 1.8Kw right?
e=W/q_h
.30 * 600
TY
dx
A heat engine is a device that converts heat energy into mechanical work. This process is governed by the laws of thermodynamics and is commonly used in machines such as car engines, power plants, and refrigerators.
To calculate the heat input for a 30% efficient heat engine, you need to know the amount of energy that the engine is able to convert into work, which is known as the thermal efficiency. This can be calculated by dividing the work output by the heat input. In this case, the thermal efficiency is 30%, so the heat input can be found by dividing the work output by 0.30.
The formula for calculating heat input is: Heat Input = Work Output / Thermal Efficiency. This formula is based on the first law of thermodynamics, which states that energy cannot be created or destroyed, only transferred or converted.
In a heat engine, the heat input is the amount of heat energy that is added to the system, while the heat output is the amount of heat energy that is released from the system. The difference between the two is the amount of heat energy that is converted into work.
No, the efficiency of a heat engine cannot be greater than 100%. This is due to the second law of thermodynamics, which states that it is impossible to convert all of the heat energy into work. The maximum theoretical efficiency of a heat engine is known as the Carnot efficiency and is determined by the temperature difference between the hot and cold reservoirs.