- #1
smillphysics
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There are four charges, each with a magnitude of 1.98 μC. Two are positive and two are negative. The charges are fixed to the corners of a 0.288-m square, one to a corner, in such a way that the net force on any charge is directed toward the center of the square. Calculate the magnitude of the net electrostatic force experienced by any charge
F=k q1*q2/ r^2 --> q1&q2 are absolute values.
k=8.99*10^9
So I used the formula above and said F= (8.99*10^9)*(1.98*10^-6)*(1.98*10^-6)/ .288^2
Then I took that answer and multipled by 2 since it was the same force on the other side. Where did I go wrong?
F=k q1*q2/ r^2 --> q1&q2 are absolute values.
k=8.99*10^9
So I used the formula above and said F= (8.99*10^9)*(1.98*10^-6)*(1.98*10^-6)/ .288^2
Then I took that answer and multipled by 2 since it was the same force on the other side. Where did I go wrong?