- #1
vileofmsz
- 1
- 0
1. Calculate the PH and the POH of the solution obtained by adding .2g of Solid KOH to 1.5 liters of .002M HCL
3.I understand this is a mol/ liter question. but I just don't understand how to transfer .2g of koh to ml and to find the concentration. I know PH= - log [Concentration Someone please help
I got KOH= 56.1g/mol. so one gram of KOH must = to 56.1 moles. If i multiply by .2 I get that .2g of KOH =11.22g
Homework Equations
3.I understand this is a mol/ liter question. but I just don't understand how to transfer .2g of koh to ml and to find the concentration. I know PH= - log [Concentration Someone please help
I got KOH= 56.1g/mol. so one gram of KOH must = to 56.1 moles. If i multiply by .2 I get that .2g of KOH =11.22g
Last edited: