- #1
Amith2006
- 427
- 2
Sir,
A loud speaker having a circular opening of diameter 20 cm is emitting sound waves uniformly. The intensity of sound at the opening is 0.2 milli watt/m^2. What is the power radiated by the source?
I solved it in the following way:
Intensity = power/Area
Here Area = (pi)R^2
= 3.14 x 0.01
= 0.0314 m^2
Power = 0.2 x 0.0314 milli watts
= 6.28 x 10^(-6) watts
Is it right?
A loud speaker having a circular opening of diameter 20 cm is emitting sound waves uniformly. The intensity of sound at the opening is 0.2 milli watt/m^2. What is the power radiated by the source?
I solved it in the following way:
Intensity = power/Area
Here Area = (pi)R^2
= 3.14 x 0.01
= 0.0314 m^2
Power = 0.2 x 0.0314 milli watts
= 6.28 x 10^(-6) watts
Is it right?