- #1
spggodd
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Homework Statement
My problem is how to calculate the Shear Flow Distribution through this open cross-section.
The section has a uniform thickness of 2mm and all other dimensions are on the attached picture.
There is also a 100 kN downwards force applied.
Homework Equations
q(s) = q(s0) = {(IxxVx(z) - IyxVx(z)) / (IyyIxx - Ixy2)} ∫s0tx*ds - {(IyyVy(z) - IyxVx(z)) / (IyyIxx - Iyx2)} ∫s0ty*ds
Where the:
I terms are the second moment of areas.
V terms relate to the applied force.
t is the thickness
y is the distance to the overall centroid of the part from the centroid of the sub-section under consideration.
ds is the distance along the sub-section.
For the rectangular sections 1 - 4 I have simplified the equation to:
q(s)=q(s0)-(Vy(z)/Ixx)∫s0ty*ds
The Attempt at a Solution
I have calculated the Second Moment of Area (500.172x10-6) m4
I have calculated all the shears flows up until point 4 on the diagram.
To the left of point 4 is a small rectangular area which I have chosen to neglect, therefore I am concentrating on the Shear Flow around a the remaining quarter annulus which will bring me back to the x-axis.
At point 4 I believe the initial shear stress = 90.168 N/mm based on my workings through the rest of the cross-section up to this point.
I am now stuck at the annulus and I can't seem to find anything in books or my course notes etc..
Thank you for your time.
Steve