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governergrimm
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Homework Statement
A crate is pulled by a force (parallel to the incline) up a rough incline. The crate has an initial speed shown in the figure below. The crate is pulled a distance of 9.33 m on the incline by a 150 N force. The acceleration of gravity is 9.8 m/s 2 . What is the change in kinetic energy of the crate? Answer in units of J.
Mass = 11kg
Angle of the incline (θ)= 20°
Initial Velocity = 1.55 m/s
μ = .308
D= 9.33 Meters
Force Applied = 150N
g=9.8
Homework Equations
Ff= μN
W=Fd=ΔKE
Fapplied -Ff=Fnetx
FnetVertical =0
The Attempt at a Solution
N-mgcosθ=0
N=mgcosθ
Fa-Ff=Fnet
Fa-μN
Fa-μmgcosθ=Fnet
150-(.308)(11)(9.8)cos(20°)=118.8
W=ΔKE = 118.8(9.33) = 1399.5
Not sure what I am missing but it is incorrect.