- #1
Embison
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The question is:
A person takes a trip, driving with a constant speed 89.7 km/h except for a 21.5 min rest stop.
If the person's average speed is 70.9 km/h, how far is the trip? Answer in units of km.
I haven't done this kind of thing for years! and I was just wondering if I solved it properly.. here is what i came up with...
time = 89.7 x (t - 21.5/60) = 70.9, 89.7 t - 38.5 = 70.9 t, t = 2.70 h
distance = 70.9 x 2.70 = 191.43 km
Is that right? Any help would be greatly appreciated.
Thanks
A person takes a trip, driving with a constant speed 89.7 km/h except for a 21.5 min rest stop.
If the person's average speed is 70.9 km/h, how far is the trip? Answer in units of km.
I haven't done this kind of thing for years! and I was just wondering if I solved it properly.. here is what i came up with...
time = 89.7 x (t - 21.5/60) = 70.9, 89.7 t - 38.5 = 70.9 t, t = 2.70 h
distance = 70.9 x 2.70 = 191.43 km
Is that right? Any help would be greatly appreciated.
Thanks