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radarspec
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A brief explanation, this assignment is to be done in Excel and also has to be turned in with handwritten solutions for finding total flight time and apex. If I can get the handwritten part done Excel is a piece of cake.
A model rocket is launched and I am to evaluate the 3 stages it goes through. During the first 0.15s the rocket (m=0.05 kg) is launched with a force of 16N. It then coasts upward while being slowed done by gravity (g=9.81m/s2. After it reaches apex(max altitude it starts to fall back down. It also deploys a parachute 6 sec. after the motor stops with a constant speed of 10 m/s until it hits ground. Calculate the speed and altitude of the rocket over it's flight time and plot them.
Knowns:
g=9.81m/s2
FE=16N
m=0.05 kg
vo=0m/s
[tex]\Delta[/tex]t=0.01s
Unknowns:
acceleration
velocity
height
total time
[tex]\Sigma[/tex]F=ma
v(t)=vo+at
h(t)=ho+vo+.5at2
Stage 1: 0[tex]\leq[/tex] t [tex]\leq[/tex] 0.15s
use dt=0.01s (was told to do this by teacher for stage 1)
[tex]\Sigma[/tex]F=ma
Fe-w=may
ay=[tex]\frac{Fe-w}{m}[/tex]
ay=[tex]\frac{16N-(0.05)(9.81)}{0.05}[/tex]=310.19m/s2
v=vo+at
v=0+(310.19)(0.15)=46.53m/s
h=ho+v0+.5at2
h=.5at2
h=.5(310.19)(0.15)2
h=10.47 m
Stage 2: 0.15 [tex]\leq[/tex] t [tex]\leq[/tex] 6.15s
[tex]\Sigma[/tex]F=ma
-w=may
ay=-g
v=vo+at
v=46.53+(9.81)(6.15)=106.86m/s
h=10.47m+(46.53)(6.15)+.5(-9.81)(6.15)2=111.11m
Stage 3: 6.15 [tex]\leq[/tex] t [tex]\leq[/tex] total time
Stage 3 is were I get lost could some point me in the right direction as to find total time and apex.
Homework Statement
A model rocket is launched and I am to evaluate the 3 stages it goes through. During the first 0.15s the rocket (m=0.05 kg) is launched with a force of 16N. It then coasts upward while being slowed done by gravity (g=9.81m/s2. After it reaches apex(max altitude it starts to fall back down. It also deploys a parachute 6 sec. after the motor stops with a constant speed of 10 m/s until it hits ground. Calculate the speed and altitude of the rocket over it's flight time and plot them.
Knowns:
g=9.81m/s2
FE=16N
m=0.05 kg
vo=0m/s
[tex]\Delta[/tex]t=0.01s
Unknowns:
acceleration
velocity
height
total time
Homework Equations
[tex]\Sigma[/tex]F=ma
v(t)=vo+at
h(t)=ho+vo+.5at2
The Attempt at a Solution
Stage 1: 0[tex]\leq[/tex] t [tex]\leq[/tex] 0.15s
use dt=0.01s (was told to do this by teacher for stage 1)
[tex]\Sigma[/tex]F=ma
Fe-w=may
ay=[tex]\frac{Fe-w}{m}[/tex]
ay=[tex]\frac{16N-(0.05)(9.81)}{0.05}[/tex]=310.19m/s2
v=vo+at
v=0+(310.19)(0.15)=46.53m/s
h=ho+v0+.5at2
h=.5at2
h=.5(310.19)(0.15)2
h=10.47 m
Stage 2: 0.15 [tex]\leq[/tex] t [tex]\leq[/tex] 6.15s
[tex]\Sigma[/tex]F=ma
-w=may
ay=-g
v=vo+at
v=46.53+(9.81)(6.15)=106.86m/s
h=10.47m+(46.53)(6.15)+.5(-9.81)(6.15)2=111.11m
Stage 3: 6.15 [tex]\leq[/tex] t [tex]\leq[/tex] total time
Stage 3 is were I get lost could some point me in the right direction as to find total time and apex.