- #1
ronaldinho52
- 8
- 0
hallo everyone,
i have here a simple problem that i cannot solve. This is the problem:
A resistor of 46 Ω is connected to the end of a power cable.
The voltage a the begin of the cable is 230 V.
The length of the cable is 25 m
The copper area is 1.0 mm2
The specific resistance of copper is 0.0175.10-6 Ω.m
What is the voltage on the resistor of 46 Ω [in V]?
I calculted this by first determining the resistance of the cable and then adding(series) both the resistance of the cable and the resistor. After this i have calculated the current in the cable. With the current known the voltage of the resistor can easily be calculated using V=IR.
This seems to be right to me but the answer is wrong. Does someone know what my mistake is and how this problem can be solved.
thanks to everyone
i have here a simple problem that i cannot solve. This is the problem:
A resistor of 46 Ω is connected to the end of a power cable.
The voltage a the begin of the cable is 230 V.
The length of the cable is 25 m
The copper area is 1.0 mm2
The specific resistance of copper is 0.0175.10-6 Ω.m
What is the voltage on the resistor of 46 Ω [in V]?
I calculted this by first determining the resistance of the cable and then adding(series) both the resistance of the cable and the resistor. After this i have calculated the current in the cable. With the current known the voltage of the resistor can easily be calculated using V=IR.
This seems to be right to me but the answer is wrong. Does someone know what my mistake is and how this problem can be solved.
thanks to everyone