How to Calculate Time it Takes for an Object to Fall or Reach the Top of an Arc

[engstudent363]

If I'm given that someone releases a ball at x distance away from the ground how do you calculate how long it takes to fall?

Another problem I have is finding the amount of time it takes to get to the top of an arc after you've thrown a ball and you're given the distance it is from the release to the top of the arc.

Both these problems assume 9.8m/s^2 acceleration.

 

[mgb_phys]

In your textbook there are three equations for the motion of objects.

v = u + a t
v^2 = u^2 + 2 a s
s = ut + 1/2 a t^2

Use the one with the variables you know.
If you don't have a textbook there is a sticky thread at the top of this forum which describes all this very carefully.

 

[Moetasim]

To calculate the time it takes for an object to fall, we can use the formula t = √(2d/g), where t is the time, d is the distance from the ground, and g is the acceleration due to gravity (9.8m/s^2). This formula assumes that the object is falling from rest and that air resistance is negligible.

For the second problem, we can use the formula t = √(2h/g), where t is the time, h is the height of the arc, and g is the acceleration due to gravity. This formula assumes that the object is thrown with an initial velocity of 0 m/s and that air resistance is negligible.

It is important to note that these calculations are based on the assumption of ideal conditions and may not be accurate in real-life scenarios where air resistance and other factors may affect the object's motion. In such cases, more complex equations and calculations may be needed to accurately determine the time it takes for an object to fall or reach the top of an arc.