How to Calculate Time Period and Frequency?

[r-soy]

A sconds pendulum taks 1 s to move from one extreme to the other

what is time period ?
what is frequency ?




what is the formula to use when found to time period and frequency the formula not written in our note

 

[The legend]

see... if you can define time period and frequency ... well, your problem would be solved!

You don't need formulas for everything... sometimes you got to make them on your own...meaning every formula can't be stuffed into any book... many change according to the given problem.

 

[r-soy]

I try ,,,,

what is time period ?

it's = 2s

what is frequency ?

but the solving frequency by formula

please hlep me .

 

[The legend]

what kinda english is that?

anyway, your time period is right and
f=1/t

 

[Borek]

what kinda english is that?

Probably non-native.

 

[r-soy]

my language is not english

anyway, f=1/t that mean 1/1 = 1 but the unit should be what ?

what happen to the time period if you take your pendulum to the moon ?

please I want your help

thanks

 

[Borek]

anyway, f=1/t that mean 1/1 = 1 but the unit should be what ?

What is unit of t? Take a look at the equation - what unit do you get from calculations?

what happen to the time period if you take your pendulum to the moon ?

Do you know any formula describing pendulum period?

 

[r-soy]

What is unit of t? Take a look at the equation - what unit do you get from calculations?


i think the answe is 1s^-a are this uint and answe correct .
Do you know any formula describing pendulum period?

what happen to the time period if you take your pendulum to the moon ?

my answer is when we increase the pendulum the time period will decrease
because there is inverse relation between time and acceleration of gravity
help me

 

[r-soy]

Borek where are you ?

 

[Borek]

I think I told you I have a life outside PF? I am playing Fallout 3 if you are really interested.

i think the answe is 1s^-a are this uint and answe correct .

s^-a - I have no idea what you mean by a, so I have no idea whether you are right or not.

my answer is when we increase the pendulum the time period will decrease because there is inverse relation between time and acceleration of gravity

Question was not about "increasing the pendulum" (whatever it should mean), but about moving it to the Moon. There is a grain of truth in your thinking - period of pendulum will change because gravitational attraction on the Moon surface differs from the attraction on the Earth surface.

 

[r-soy]

sorry i mean s^-1 is this correct .

about (period of pendulum) will change because gravitational attraction on the Moon surface differs from the attraction on the Earth surface.

here (period of pendulum) or (period of time )

 

[Borek]

s^-1 is correct. This unit has its own name - Hertz (Hz).

OK, period of pendulum will change - but will it get longer, or shorter?

 

[r-soy]

it will come shorter

 

[The legend]

^^ i don't think so...

 

[Borek]

What is the formula used for period calculation, which values are constant and which are changing when you move from the Earth to Moon?