- #1
atlas_2010
- 13
- 1
Hello all,
I am not very sure with this kind of weld check, could you give me some help and suggestion?
Details as following:
Given:
Ft=force in y direction
Lt=distance between Ft action point and weld group geometric center(y direction)
Fl=force in x direction
Ll=distance between Fl action point and weld group geometric center(x direction)
L1=weld 1 length
L2=weld 2 length
L3=weld 3 length
t=weld throat
Ix-=moment interia about x axial
Iy-=moment interia about y axial
r=the max distance form center
Soluation
find out the max weld stress
My solution is this,
First move Ft and Fl to the geometric center get the tension and shear stress
Then take tousionT=Ft*Lt+Fl*Ll(or Ft*Lt-Fl*Ll) take the
stress σ=T/(Ix+Iy)*r,and distribute the result to x and y direction,
and finally get eqivualent stress
Am I right?
Thank you for your help and suggestion.
I am not very sure with this kind of weld check, could you give me some help and suggestion?
Details as following:
Given:
Ft=force in y direction
Lt=distance between Ft action point and weld group geometric center(y direction)
Fl=force in x direction
Ll=distance between Fl action point and weld group geometric center(x direction)
L1=weld 1 length
L2=weld 2 length
L3=weld 3 length
t=weld throat
Ix-=moment interia about x axial
Iy-=moment interia about y axial
r=the max distance form center
Soluation
find out the max weld stress
My solution is this,
First move Ft and Fl to the geometric center get the tension and shear stress
Then take tousionT=Ft*Lt+Fl*Ll(or Ft*Lt-Fl*Ll) take the
stress σ=T/(Ix+Iy)*r,and distribute the result to x and y direction,
and finally get eqivualent stress
Am I right?
Thank you for your help and suggestion.