- #1
Leumas13
- 2
- 0
So, I've been asked to show that
f(x)=Ʃn=0∞ [ansin(nπx/a) + bncos(nπx/a)
is equivalent to f(x)=Ʃn=-∞∞ cneinx/a
I'm kinda stuck. i want to turn this into the exponential form but I don't see how to condense this into a single term.
Thanks!
f(x)=Ʃn=0∞ [ansin(nπx/a) + bncos(nπx/a)
is equivalent to f(x)=Ʃn=-∞∞ cneinx/a
I'm kinda stuck. i want to turn this into the exponential form but I don't see how to condense this into a single term.
Thanks!