- #1
LightPhoton
- 22
- 3
Let the representation of a Hermitian Operator in some basis ##x## be
$$\hat A\equiv A(x)$$
and let
$$\psi(x)=\langle x\vert\psi\rangle$$
Then we define
$$A(x)\,\psi(x)=\langle x\vert\hat A\vert\psi\rangle$$
This is the Wikipedia article that mentions this.
From here how do we derive the momentum operator (or any other) on a position basis?
$$\hat A\equiv A(x)$$
and let
$$\psi(x)=\langle x\vert\psi\rangle$$
Then we define
$$A(x)\,\psi(x)=\langle x\vert\hat A\vert\psi\rangle$$
This is the Wikipedia article that mentions this.
From here how do we derive the momentum operator (or any other) on a position basis?
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