How to Derive Power for a Drone Hovering Using a Capacitor?

  • Thread starter Chris Johns
  • Start date
In summary, the conversation discusses the power required for a small copter drone to stay in the air, which is calculated to be mgv/2. It also mentions the significance of controlling power distribution and the role of the propeller in generating force through pushing air downward at a velocity v. The problem is not yet solved and the speaker is seeking assistance in understanding the concept further.
  • #1
Chris Johns
2
0
Member advised to fill out the template, especially the attempt at solution, for all homework help requests.
A 1 F capacitor is charged at 10 Volt and powers a small copter drone of m=20 grams.
The copter generates a vertical lift to balance gravity. It does this with a
propeller than pushes air downward at a velocity v. Show that the power required
is mgv/2. At an air flow velocity of 2 m/s , calculate how long the copter stays up
(assuming 100% energy efficiency and controlling the power distribution to be
steady).
 
Physics news on Phys.org
  • #2
Chris Johns said:
A 1 F capacitor is charged at 10 Volt and powers a small copter drone of m=20 grams.
The copter generates a vertical lift to balance gravity. It does this with a
propeller than pushes air downward at a velocity v. Show that the power required
is mgv/2. At an air flow velocity of 2 m/s , calculate how long the copter stays up
(assuming 100% energy efficiency and controlling the power distribution to be
steady).

PF rules require some effort on your part. Try solving the problem for yourself, and if you are stuck on some issue, come back here and explain the difficulty. Maybe then you can be receive help.
 
  • #3
I've been trying for a week now! I know that
Power = rateOfDoingWork

Work = Force * Distance = mass * g * Distance

Power = d/dt (Work) = d/dt (Force * Distance) = d/dt (Force)* Distance + d/dt (Distance) * Force

also d/dt(Force) goes to zero because mass (m) is constant and gravitational acceleration (g) is constant.

Thus Power = m * g * v

But I can't go any further than this. I would greatly appreciate any help.
 
  • #4
For the blades to generate a force what must they do to the air?
 

Related to How to Derive Power for a Drone Hovering Using a Capacitor?

1. What is the formula for power?

The formula for power is P = mgv/2, where P represents power, m represents mass, g represents gravitational acceleration, and v represents velocity.

2. How do you prove that power=mgv/2?

To prove that power=mgv/2, you can use the formula P = Fv, where F represents force. By substituting mgv/2 for F, you can see that P = (mgv/2)v = mgv2/2. This is equivalent to P = mgv/2, thus proving the formula.

3. What are the units for power in the formula mgv/2?

The units for power in the formula mgv/2 are watts (W), as power is measured in joules per second (J/s) and the unit for joules is equivalent to the unit for watts.

4. Can power=mgv/2 be applied to all situations?

No, the formula P = mgv/2 is specifically for calculating the power of an object moving at a constant speed in a straight line due to a constant force. It cannot be applied to all situations.

5. How does the formula mgv/2 relate to the concept of work?

The formula mgv/2 is derived from the work-energy theorem, which states that the work done on an object is equal to the change in its kinetic energy. In this case, the work done on an object is equal to mgv/2, which is also the formula for power.

Similar threads

  • Introductory Physics Homework Help
Replies
12
Views
1K
Replies
15
Views
1K
  • Other Physics Topics
Replies
8
Views
1K
Replies
1
Views
1K
  • Introductory Physics Homework Help
Replies
11
Views
3K
  • Introductory Physics Homework Help
Replies
13
Views
4K
  • Introductory Physics Homework Help
Replies
4
Views
2K
  • DIY Projects
Replies
32
Views
6K
  • Introductory Physics Homework Help
Replies
1
Views
1K
  • Introductory Physics Homework Help
Replies
1
Views
1K
Back
Top