How to Derive the Wave Equations for Photons?

In summary, the conversation discusses using the relativistic expression for energy to find a wave equation for photons. It is mentioned that photons are quanta of fields and the differential equation for the quantized electromagnetic field is obtained by applying canonical quantization to the classical electrodynamic equation. However, it is stated that this approach may not be helpful as the photon does not have a wave equation. The correct approach is to use the field equation for the electric field, which can be derived from Maxwell's equations in vacuum.
  • #1
jb646
12
0

Homework Statement


Use the relativistic expression for energy E^2=p^2c^2+(m_0)^2(c)^4 to find a wave equations for photons. Find a solution for ψ and compare to the electric field (hint: photons are massless, E_op=ih(d/dt) and p_op=h/i(d/dx)


Homework Equations


the only equations i know are the ones given in the problem


The Attempt at a Solution


if somebody could please point me in the right direction, i do not have the mental power to understand what i should even try to do first. Thanks for any help you can provide.
 
Physics news on Phys.org
  • #2
Photons are quanta of fields, it doesn't really work the way your problem suggests.

The differential equation for the quantized electromagnetic field is obtained by applying a canonical quantization* to the classical electrodynamic equation for the one-forms describing the field at a classical level.

* very tricky issue.
 
  • #3
jb646 said:

Homework Statement


Use the relativistic expression for energy E^2=p^2c^2+(m_0)^2(c)^4 to find a wave equations for photons. Find a solution for ψ and compare to the electric field (hint: photons are massless, E_op=ih(d/dt) and p_op=h/i(d/dx)


Homework Equations


the only equations i know are the ones given in the problem


The Attempt at a Solution


if somebody could please point me in the right direction, i do not have the mental power to understand what i should even try to do first. Thanks for any help you can provide.
Okay, if E_op=ih(d/dt), then what would E_op2 be?

bigubau said:
Photons are quanta of fields, it doesn't really work the way your problem suggests.

The differential equation for the quantized electromagnetic field is obtained by applying a canonical quantization* to the classical electrodynamic equation for the one-forms describing the field at a classical level.

* very tricky issue.
I fail to see how that is helpful.
 
  • #4
Redbelly98 said:
I fail to see how that is helpful.

The problem is wrong. The photon has no wave equation. The electric field has a field equation, but in the classical sense, as it can be deduced from Maxwell's equations (for simplicity, in vacuum).
 
  • #5


I would approach this problem by first understanding the equations given in the problem. The relativistic expression for energy, E^2=p^2c^2+(m_0)^2(c)^4, is known as the energy-momentum relation and it describes the total energy of a particle (including its rest mass energy) in terms of its momentum and the speed of light. The other equations, E_op=ih(d/dt) and p_op=h/i(d/dx), are related to the properties of operators in quantum mechanics.

To find a wave equation for photons, we need to use the energy-momentum relation and the properties of operators. Since photons are massless particles, we can set m_0=0 in the energy-momentum relation. This gives us E=pc, where p is the momentum of the photon. We can also use the properties of operators to write the energy and momentum operators in terms of the electric field operator (E_op=ih(d/dt)) and the momentum operator (p_op=h/i(d/dx)).

Substituting these expressions into the energy-momentum relation, we get (E_op)^2=(p_op)^2c^2. Now, we can use the properties of operators to rewrite this equation as (ih(d/dt))^2=(h/i(d/dx))^2c^2. Simplifying this equation, we get -(d^2/dt^2)=(d^2/dx^2)c^2. This is the wave equation for photons, which is a second-order differential equation in both time and position.

To find a solution for ψ, we need to solve this wave equation. This can be done using standard techniques from differential equations. Once we have a solution for ψ, we can compare it to the electric field operator. This comparison will give us insights into the wave-like nature of photons and how they are related to the electromagnetic field.
 

FAQ: How to Derive the Wave Equations for Photons?

What is a wave equation for photons?

A wave equation for photons is a mathematical equation that describes the behavior and characteristics of photons, which are particles of light that exhibit both wave-like and particle-like properties. It is used to predict the motion and interactions of photons in various situations, such as in electromagnetic fields or during the process of emission or absorption.

How is a wave equation for photons derived?

A wave equation for photons is derived from the principles of quantum mechanics and the theory of relativity. It involves using mathematical equations and operators to describe the wave-like properties of photons, such as their frequency and wavelength, as well as their particle-like properties, such as their energy and momentum.

What are the key components of a wave equation for photons?

The key components of a wave equation for photons include the speed of light (c), Planck's constant (h), and the energy and momentum operators. These components are used to describe the relationship between the wave properties and particle properties of photons, and how they interact with other particles and fields.

How is a wave equation for photons different from other wave equations?

A wave equation for photons is different from other wave equations because it involves both wave-like and particle-like properties, whereas other wave equations typically only describe one type of behavior. Additionally, the wave equation for photons is derived from the principles of quantum mechanics and relativity, which are unique to the behavior of particles at the atomic and subatomic level.

What are some real-world applications of a wave equation for photons?

A wave equation for photons has many real-world applications, such as in the field of optics where it is used to describe the behavior of light in lenses, mirrors, and other optical devices. It is also used in the development of technology such as lasers, fiber optics, and solar cells. Additionally, understanding the wave equation for photons is crucial in fields such as astronomy, where it is used to study the behavior of light from distant celestial objects.

Similar threads

Back
Top