- #1
HumorMe81
- 17
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So confused about standing waves in a closed pipe, which is open at one end and closed at the other. The closed end has a node while the open end has an antinode. To figure the wavelength, i use the formula:
Lambda = 4L/n where n is the number of harmonic and can only be odd integers
frequency of the wave, f = nv/4L
How can i figure out the number of nodes or antinodes? For example, the first harmonic is the fundamental frequency and has one node and one antinode. the third harmonic is the first overtone and has two nodes and two nodes. the fifth harmonic is the second overtone and has three nodes and three antinodes. What if I come across a situation where I'm dealing with n=53, is there a formula i can employ to figure out the number of nodes and antinodes?
Thanks!
Lambda = 4L/n where n is the number of harmonic and can only be odd integers
frequency of the wave, f = nv/4L
How can i figure out the number of nodes or antinodes? For example, the first harmonic is the fundamental frequency and has one node and one antinode. the third harmonic is the first overtone and has two nodes and two nodes. the fifth harmonic is the second overtone and has three nodes and three antinodes. What if I come across a situation where I'm dealing with n=53, is there a formula i can employ to figure out the number of nodes and antinodes?
Thanks!