How to Diagonalize Hamiltonian in Bloch Approximation for Spin Systems?

  • Thread starter Petar Mali
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In summary, the conversation discusses the diagonalization of the Hamiltonian in Bloch approximation. The first step is to write S^x in terms of raising and lowering operators, and then replace spin with Bose operators. To calculate spin waves, a reference ground state must be chosen and the boson operators must be Fourier transformed. The presence of a single S_z operator is unusual for spin wave theory, but if it does not result in a single boson operator, it may not be a problem. There is also a question about the placement of the two S_x operators and the order of the summation.
  • #1
Petar Mali
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How to diagonalise Hamiltonian in Bloch approximation?

[tex]\hat{H}=-\frac{1}{2}\sum_{\vec{n},\vec{m}}I_{\vec{n},\vec{m}}\hat{S}_{\vec{n}}^x\hat{S}_{\vec{n}}^x-\Gamma\sum_{\vec{n}}\hat{S}_{\vec{n}}^z[/tex]
 
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  • #2
I would start by writing S^x in terms of raising and lowering operators. What is the Bloch approximation?
 
  • #3
Replacing spin with Bose operators I think!

[tex]S_{\vec{n}}^+=\sqrt{2S}B_{\vec{n}}[/tex]


[tex]S_{\vec{n}}^-=\sqrt{2S}B_{\vec{n}}^+[/tex]


[tex]S-S_{\vec{n}}^z=B_{\vec{n}}^{+}B_{\vec{n}}[/tex]
 
  • #4
So, maybe a little more background would be helpful. What exactly is your question?

If you want to calculate spin waves you need to choose a reference ground state which will affect the form of your Bose operators (right now it looks like you've chosen a ferromagnetic ground state). For spin waves then you need to Fourier transform your boson operators.

But I am a bit surprised by the appearance of the lone S_z operator, because usually the presence of a single spin operator is a problem for spin wave theory. But since S_z won't result in a single boson operator then it might be ok. Also, are both S_x operators acting on the same site, or is that a typo? If that's correct, you should carry out the sum over m first.
 

Related to How to Diagonalize Hamiltonian in Bloch Approximation for Spin Systems?

1. What is diagonalisation in the context of Bloch approximation?

Diagonalisation in the context of Bloch approximation refers to the process of transforming a matrix into a diagonal matrix, where the elements on the diagonal represent the eigenvalues of the original matrix. This technique is commonly used in quantum mechanics to simplify calculations and solve equations.

2. How does diagonalisation relate to the Bloch approximation method?

The Bloch approximation method is based on the assumption that the wave function of a particle in a periodic potential can be approximated by a linear combination of plane waves. Diagonalisation is used to determine the coefficients of these plane waves, which are then used to calculate the energy levels and wave functions of the system.

3. What is the importance of diagonalisation in the Bloch approximation?

Diagonalisation is essential in the Bloch approximation as it allows for a more efficient and accurate calculation of the energy levels and wave functions of a system. It also helps to simplify complex equations and make them more manageable for analysis and interpretation.

4. Can diagonalisation be applied to systems with more than one dimension?

Yes, diagonalisation can be applied to systems with multiple dimensions, such as two or three-dimensional systems. This technique is commonly used in solid-state physics to study the behavior of electrons in crystals.

5. Are there any limitations to the Bloch approximation and diagonalisation method?

Yes, the Bloch approximation and diagonalisation method have limitations in certain scenarios, such as when the potential is not periodic or when strong interactions between particles are present. In these cases, more advanced techniques may be necessary to accurately describe the system.

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