How to Divide by 9 and Find Remainders

  • Thread starter jim1174
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So, we can say that 9 goes into 24 2 times with a remainder of 6. In summary, to solve the problem, we first divide 9 into 44, getting a quotient of 4 and a remainder of 8. Then, we bring down the 3 and divide 9 into 83, getting a quotient of 9 and a remainder of 2. Finally, we bring down the 4 and divide 9 into 24, getting a quotient of 2 and a remainder of 6. This pattern continues until there are no more numbers to bring down.
  • #1
jim1174
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I got this problem off the internet and need some help understanding how to do it. first you do 9 goes into 44 4 times so you put a 4 on top then you do 9 times 4 equals 36 so you put the 36 under the 44. next you do 44 minus 36 which is 8 and bring down the 3. can you please explain how to get the other numbers in the problem ?
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  • #2
If I tell you that 9 goes into 83 9 times, can you take it the rest of the way?
 
  • #3
ok so where does the 2 on the top come from ?
 
  • #4
9 x 9 = 81, subtract that from the 83, gives you 2, bring down the 4 -----
Starting to see the pattern?
 
  • #5
yes i understand that part but how do you get the 2 on the top next to the 49
 
  • #6
9 goes into 24 2 times
 
  • #7
9*2= 18< 24< 27= 9*3

Since "9*3" is too large, we take "2" leaving a remainder of 24- 18= 6.
 

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