How to Evaluate lim_{x->0^{+}}(1+sinx)^{\frac{1}{\sqrt{x}}}?

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The limit lim_{x->0^{+}}(1+sinx)^{\frac{1}{\sqrt{x}}} results in an indeterminate form of 1^{\infty}. To evaluate this limit, it is suggested to use the identity 1+sin(x)=e^{ln(1+sin(x))}. This transformation allows for the application of logarithmic properties to simplify the expression. The discussion emphasizes the importance of recognizing indeterminate forms in limit evaluations. Ultimately, proper manipulation of the expression leads to a clearer path for finding the limit.
nhrock3
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lim_{x->0^{+}}(1+sinx)^{\frac{1}{\sqrt{x}}}



i get here 1^{\infty} form which states that's its some sort of exponent
 
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nhrock3 said:
lim_{x->0^{+}}(1+sinx)^{\frac{1}{\sqrt{x}}}



i get here 1^{\infty} form which states that's its some sort of exponent

Use "[ tex]" with no space in front of the 't' and "[ /tex]" with no space in front of the '/'. Capital letters do not work.

RGV
 
lim_{x->0^{+}}(1+sinx)^{\frac{1}{\sqrt{x}}}

Use the identity 1+sin(x)=e^{ln(1+sin(x))}.

ehild
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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