- #1
Wiz14
- 20
- 0
The Following is defined,
log2004(log2003(log2002(log2001x)))
where x > c, what is c?
Answer is 2001^2002, but how to obtain it?
I do not know much about logs as I am only in precalculus.
log2004(log2003(log2002(log2001x)))
where x > c, what is c?
Answer is 2001^2002, but how to obtain it?
I do not know much about logs as I am only in precalculus.