How to Find Max and Min Points for \(\frac{x^3}{2} - |1 - 4x|\) in \((0, 2)\)?

In summary: The first sentence is saying that for all x within the range [0, 2], x is greater than or equal to 0.4. The second sentence is saying that x lies between 0 and 2, inclusive.
  • #1
Petrus
702
0
Calculate max and min point to function \(\displaystyle \frac{x^3}{2}-|1-4x|\) in the range \(\displaystyle \left(0,2 \right)\)
I got one question, shall I ignore when it's \(\displaystyle \frac{x^3}{2}-(-1+4x)\) cause then \(\displaystyle x<0\) and that don't fit in my range? Do I got correct?
 
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  • #2
\(\displaystyle |1-4x|=-(1-4x) \,\,\, \,\,\,\forall \,\,\, x>\frac{1}{4}\)
 
  • #3
ZaidAlyafey said:
\(\displaystyle |1-4x|=-(1-4x) \,\,\, \,\,\,\forall \,\,\, x>\frac{1}{4}\)
So I basicly got wrong? (I have not done this kind of problem with aboslute value)
If I understand correct so I will have
\(\displaystyle |1-4x|=-(1-4x) \,\,\, \,\,\,\forall \,\,\, x>\frac{1}{4}\) that means i got new range on that? \(\displaystyle \left(\frac{1}{4},2 \right)\)
\(\displaystyle |1-4x|=-(-1+4) \,\,\, \,\,\,\forall \,\,\ x<\frac{1}{4} \) that means my new range is \(\displaystyle \left(0,\frac{1}{4} \right)\) I am right? If so shall I derivate both and find crit point?
 
  • #4
Do you mean the domain ? Because the domain represents the values for x but the range represents the values for y
 
  • #5
ZaidAlyafey said:
Do you mean the domain ? Because the domain represents the values for x but the range represents the values for y
Yeah I mean domain, Thats what the problem is asking for :P? Sorry I did not know it's called domain in english
 
  • #6
Ok , then you are correct , derive each function separately .
 
  • #7
let's make them to case 1 and case 2
Case 1:
\(\displaystyle |1-4x|=-(1-4x) \,\,\, \,\,\,\forall \,\,\, x>\frac{1}{4}\) \(\displaystyle \left(\frac{1}{4},2 \right)\)
Our function become \(\displaystyle \frac{x^3}{2}-1+4x\)
If we derivate the function we get \(\displaystyle \frac{3x^2}{2}+4\)
Now we want to find critical point \(\displaystyle \frac{3x^2}{2}+4=0\)
So I factor out \(\displaystyle \frac{1}{2}\) and get \(\displaystyle \frac{1}{2}(3x^2+8)=0\) and our critical point (complex) are \(\displaystyle x_1=\sqrt{\frac{-8}{3}}\) and \(\displaystyle x_2=-\sqrt{\frac{-8}{3}}\) I guess we shall ignore case 1 cause we got complex roots.
Case 2:
\(\displaystyle |1-4x|=-(-1+4) \,\,\, \,\,\,\forall \,\,\ x<\frac{1}{4} \) \(\displaystyle \left(0,\frac{1}{4} \right)\)
Our function become \(\displaystyle \frac{x^3}{2}+1-4x\)
If we derivate the function we get \(\displaystyle \frac{3x^2}{2}-4\)
Now we want to find critical point \(\displaystyle \frac{3x^2}{2}-4=0\)
So I factor out \(\displaystyle \frac{1}{2}\) and get \(\displaystyle \frac{1}{2}(3x^2-8)=0\) and our critical point are: \(\displaystyle x_1:\sqrt{\frac{8}{3}}\) and \(\displaystyle x_2:-\sqrt{\frac{8}{3}}\) but our \(\displaystyle x_2\) does not fit our domain so we shall ignore it. I am correct so far? What shall I do next?
 
  • #8
Hi Petrus. It looks pretty good to me, but also hope someone else checks for any errors. What you should do now is plug in a bunch of stuff into the original f(x). When you have a restricted domain and you're trying to find minimums and maximums you should also test out:

1) Critical points
2) End points of the domain

So in this case you found just one critical point, \(\displaystyle x=\sqrt{\frac{8}{3}}\). Find the following values and then determine where you have a maximum and minimum. \(\displaystyle f \left( \sqrt{\frac{8}{3}} \right), \hspace{1 mm} f(0), \hspace{1 mm} f \left( \frac{1}{4} \right), \hspace{1 mm} f(2)\)
 
  • #9
Hello,
Thanks ZaidAlyafey and Jameson for the help! I did correct answer!:)(Bow)(Dance)
after input all those point into orginal function and look for highest value ( not wealth :P) and lowest value, I get the answer
max: \(\displaystyle \frac{1}{128}\)
min: \(\displaystyle 1-\frac{16\sqrt{\frac{2}{3}}}{3}\)
edit: what does \(\displaystyle \,\,\, \,\,\,\forall \,\,\,\) means in words?
 
Last edited:
  • #10
Cool :) So you're saying you've confirmed that you have found the correct answer?
 
  • #11
Jameson said:
Cool :) So you're saying you've confirmed that you have found the correct answer?
Hello Jameson
Indeed I did thanks to you and ZaidAlyafey ( problem we get is online problem that means we put in our answer and it give us 'correct' or 'wrong' and I got 'correct') I also edit my early post if anyone could tell me what \(\displaystyle \,\,\, \,\,\,\forall \,\,\,\) that means in words :)
 
  • #12
Great! I'm going to mark this thread [SOLVED] then.

$\forall$ means "for all" or "for every". Earlier you wrote this:

\(\displaystyle \forall x>\frac{1}{4} \left(\frac{1}{4},2 \right)\)

which is a bit confusing. I think I know what you meant though and in my opinion it's better and more conventional to write it like this:

i) \(\displaystyle \forall x \in \left[ \frac{1}{4},2 \right] \) or

ii) \(\displaystyle x \mid \frac{1}{4}\le x \le 2\)
 

FAQ: How to Find Max and Min Points for \(\frac{x^3}{2} - |1 - 4x|\) in \((0, 2)\)?

1. What is the difference between Max and point 2?

Max refers to the maximum value in a set of numbers or data points. Point 2, on the other hand, is a specific data point or value within that set.

2. How is absolute value related to Max and point 2?

Absolute value is a mathematical concept that measures the distance of a number from 0 on a number line. In the context of Max and point 2, absolute value can be used to find the distance between the two values.

3. Can Max and point 2 be negative numbers?

Yes, both Max and point 2 can be negative numbers. The concept of absolute value allows for negative numbers to be represented as positive distances from 0 on a number line.

4. How is Max and point 2 used in data analysis?

Max and point 2 can be used to identify the highest and specific data points in a set of data. This information can then be used to make comparisons, calculate averages, and draw conclusions about the data.

5. Is it possible for Max and point 2 to be the same value?

Yes, it is possible for Max and point 2 to be the same value if the set of data only contains one unique value. In this case, both Max and point 2 would refer to that same value.

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