How to Find Net Torque and Angular Momentum in a Pulley System?

In summary: You should have a variable in your equation that lets you find the torque from the force. Then you can find alpha from Torque = I*alpha.In summary, the problem involves a spaceship rotating at 6 rev/min and the occupants want to stop the rotation. The spaceship has small jets mounted tangentially, 3m from the axis, that can eject 10g/s of gas with a nozzle velocity of 800 m/s. The rotational inertia of the ship is 4000 kg*m^2. To solve the problem, we can use the formula F = d/dt(mv) to calculate the torque caused by the jets, and then use the formula Torque = I*alpha to find the angular acceleration
  • #1
nns91
301
1

Homework Statement



1. There is m1 on an incline connected to m2 by a string through the pulley at the top of the incline. The incline is frictionless and the string pases through the center of mass of each block. The pulley has a moment of inertia I and a radius r. (a) Find the net torque acting on the system. (b) Write an expression for the total angular momentum of the system about the center of the pulley when the masses are moving with a speed v. (c) Find the acceleration of the masses from your results for parts (a) and (b) by setting the net torque equal to the rate of change of the angular momentum of the system

Homework Equations



Torque=dL/dt
L=I*w
T=F*r

The Attempt at a Solution



1. So I used Newton's 2nd law to get the acceleration as:
(m2*g*sin[tex]\theta[/tex]- m1*g)/ (m1+m2+(1/2)M)

However, M which is mass of the pulley is not given. I can make M=2I/r^2

I still don't get the right answer for net torque. It should be rg(m2*sin[tex]\theta[/tex]-m1)

Anyone know if I am on the right track ?? Any help will be appreciated
 
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  • #2
m1 on an incline connected to m2 by a string through the pulley at the top of the incline

I'm picturing m1 on a ramp at angle theta with the horizontal so that the force on it along the ramp is m1*g*sin(theta). Also, m2 hanging straight down from the pulley, with force m2*g.
But this would give a torque of (m2*g - m1*g*sin(theta))*r
or rg(m2 - m1*sin(theta)).

I must be mistaken about where the masses are?
 
  • #3
m2 should be on the ramp and m1 should be hanging.

How about other parts. I think I get part a now.
 
  • #4
L = Iw for the turning pulley.
plus mvr for the moving masses.
 
  • #5
For part a, just to make sure, why are tensions not taken into account ?
 
  • #6
The tension in the string just transfers the force from one object to another.
If you think of the whole thing (strings and masses) being one object you don't need to bother with tension. Usually.

If we ignore the moment of inertia of the pulley in this problem, we could think of it as one object and write
m1*g - m2*g*sin(A) = (m1 + m2)*a

or we could write T - m2*g*sin(A) = m2*a for the mass on the ramp and
m1*g - T = ma for the hanging mass.
If you add these two equations together, the T's annihilate and you get the first equation 4 lines up.

Of course none of this helps in your problem where you have moment of inertia to deal with.
EDIT: actually, calculating "a" this way is a big help. If we temporarily let I = 0 in the acceleration we get using the torque - angular momentum approach, it simplify to
a = (m1*g = m2*g*sin(A))/(m1 + m2) from the equation above.
 
  • #7
Thanks. I could solve it now

Another problem:

A spaceship rotates about its longitudinal axis at 6 rev/min. The occupants wish to stop this rotation. They have small jets mounted tangentially, at a distance R=3m from the axis, as indicated, and can eject 10g/s of gas from each jet with a nozzle velocity of 800 m/s. For how long must they turn on these jets to stop the rotation ? To rotational inertia of the ship around its axis (assumed to be constant) is 4000 kg*m^2

Any hint on how I should approach this one ?
 
  • #8
the force exerted by one of those "jets" is F = d/dt(mv) = v*dm/dt
where dm is the mass ejected in time dt and v is the exhaust velocity.
You should be able to work out the torque from that and the radius.
Do you have a formula relating torque and inertia (analogous to F = ma)?
 
  • #9
how do I calculate alpha though ?

Should it be m*dv/dt instead of v*dm/dt ??
 
  • #10
Should it be m*dv/dt instead of v*dm/dt ??

Actually it is d/dt (mv) = dm/dt*v + m*dv/dt
Since the velocity of he exhaust is constant, the second term is zero so
F = v*dm/dt

To calculate alpha (angular acceleration), you need some formula analogous to F = ma relating the Torque to the angular acceleration. Do you have any formulas that say "Torque = ..." ?
 
  • #11
I know Torque= I*alpha.

I have I but Toruqe and alpha are unknown so how can I calculate ?
 
  • #12
You can figure out the torque caused by those jets since you know the force each one exerts.
 

FAQ: How to Find Net Torque and Angular Momentum in a Pulley System?

What is angular momentum?

Angular momentum is a property of rotating objects that describes their tendency to keep rotating. It is a vector quantity that depends on an object's mass, speed, and distance from the axis of rotation.

How is angular momentum different from linear momentum?

Linear momentum is a property of objects in motion that describes their tendency to keep moving in a straight line. Angular momentum is a property of rotating objects that describes their tendency to keep rotating around an axis. While linear momentum is a straight-line motion, angular momentum is a rotational motion.

What are some real-life examples of angular momentum?

Some common examples of angular momentum include spinning tops, rotating tires on a car, and the Earth's rotation around its own axis. Other examples include a spinning figure skater, a rotating fan, and a swinging pendulum.

How do you calculate angular momentum?

Angular momentum is calculated by multiplying an object's moment of inertia (a measure of its resistance to rotation), its angular velocity (how fast it is rotating), and its distance from the axis of rotation.

How is angular momentum conserved?

According to the law of conservation of angular momentum, the total angular momentum of a system remains constant as long as there are no external torques acting on the system. This means that if one part of a system increases its angular momentum, another part must decrease by an equal amount to maintain the total angular momentum of the system.

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