- #1
Chester8990
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Homework Statement
Okay so this problem was in my test i did yesterday. While I finished it my teacher handed me the answers. Then i found his answer was half of mine for this question. But both answers seemed to be correct..
A projectile was launched from a trebuchet, the arm on the trebuchet has a mass of 10kg and the centre of mass is at the middle of the whole 10m length, which is also the centre of rotation.
It is known that the arm traveled 1/3 of a circle in 0.36s. Find the torque in this time interval.
SO.
mass=10kg
Length=10m
Time=0.36s
Omega(ω)(Angular velocity)=?
Moment of inertia(I)=?
Alpha(α)(Angular acceleration)=?
Torque(τ)=?
Homework Equations
Δθ=ωi*1/2 αt2
I=(mL2)/12
τ=Iα
The Attempt at a Solution
ω=[(2π)/3]/0.36s
ω=5.817764173rad/s
I=[(10kg)(10m)2]/12
I=83.33333kg*m2
Δθ=ωi*1/2 αt2
since ωi = 0
Δθ=1/2 αt2
α=(2Δθ)/t2
α=[2*(2π)/3]/(0.36)2
α=32.32091207rad/s2
τ=Iα
τ=(83.33333kg*m2)(32.32091207rad/s2)
τ=2693.409338N.m
The answer sounds reasonable, until i use another equation to find α
α=Δω/Δt
α=(5.817764173rad/s)/0.36s
α=16.16045604rad/s2
This is how my teacher calculated his angular acceleration...
The different angular acceleration value will inevitably change the torque...
But both methods seemed to be correct...
Would you please help satisfy my curiosity? And possibly saving a few points in my test!
Thank you very much! :P