- #1
Reshma
- 749
- 6
Equation of a hypocycloid is:
[tex]x^{3/2} + y^{3/2} = a^{3/2}[/tex].
Find the area of the figure bounded by this hypocycloid.
My work:
I can use the plane polar coordinates here taking [itex]x = a\cos t[/itex] & [itex]y = a\sin t[/itex] with [itex]t = [0, 2\pi][/itex]. But I don't know how to obtain the surface integral for evaluating the area ( ) . Someone help me.
[tex]x^{3/2} + y^{3/2} = a^{3/2}[/tex].
Find the area of the figure bounded by this hypocycloid.
My work:
I can use the plane polar coordinates here taking [itex]x = a\cos t[/itex] & [itex]y = a\sin t[/itex] with [itex]t = [0, 2\pi][/itex]. But I don't know how to obtain the surface integral for evaluating the area ( ) . Someone help me.