- #1
Jessica Lewis
- 3
- 0
The question is:
a bullet that is shot from a target is traveling at an initial speed of 80 m/s and it is 6 m away from its target. The target is wearing a bullet proof vest that is 0.26 m thick. As the bullet makes contact with the vest is slows down at a rate of 9000 m/s2. What is the final velocity of the equation?I would assume that the equation used would be Vf^(2) = Vi^(2) + 2ad, however each time I attempt this question I get an answer that makes absolutely no sense.
So, please help me,
Thank you! :)
a bullet that is shot from a target is traveling at an initial speed of 80 m/s and it is 6 m away from its target. The target is wearing a bullet proof vest that is 0.26 m thick. As the bullet makes contact with the vest is slows down at a rate of 9000 m/s2. What is the final velocity of the equation?I would assume that the equation used would be Vf^(2) = Vi^(2) + 2ad, however each time I attempt this question I get an answer that makes absolutely no sense.
So, please help me,
Thank you! :)