- #1
telekom90
- 1
- 0
Homework Statement
Assume a Gaussian laser beam ( 1064 nm wavelength) having an FWHM-diameter(intensity) of 5 mm. By transmission through a thin nonlinear crystal, a new wave is generated that is proportional to the square of the incoming field (and therefore radiates at twice the frequency, or 532nm wavelength). This second harmonic (SH) beam co-propagates with the fundamental laser beam. What is the FWHM-diameter of the SH beam?
Homework Equations
dFWHM = ω(z)√2ln2
The Attempt at a Solution
λ =1064nm, dFWHM=5 mm##, ## λSH=532 nm .
I can't solve this problem because I don't know how to relate this equation "dFWHM=ω(z)√2ln2= 5mm " with the FWHM-diameter of second harmonic (SH) beam?!