- #1
Casio1
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I want to find the coordinates of any points at which the circle x^2 + y^2 + 6x - 8y + 20 = 0
I have an equation y = -2x - 2
I have tried the following but am struggling with the final understanding.
(x + 3)^2 + (y - 4)^2 = 5
(x + 3)^2 = x^2 + 6x +9
(y - 4)^2 = 4x^2 + 24x + 36
combining and cancelling gives
5x^2 + 30x + 39 = 0
I now require to find the factors, which I am struggling with, I am thinking
x^2 + 10x + 13
In my head I have these numbers running round, factors 3, 6 and 5. I know there is a method to working this out like 3 x 13 = 39, and 6 x 5 = 30 etc, but I just can't seem to grasp it?
Any help appreciated
Thanks(Wondering)
I have an equation y = -2x - 2
I have tried the following but am struggling with the final understanding.
(x + 3)^2 + (y - 4)^2 = 5
(x + 3)^2 = x^2 + 6x +9
(y - 4)^2 = 4x^2 + 24x + 36
combining and cancelling gives
5x^2 + 30x + 39 = 0
I now require to find the factors, which I am struggling with, I am thinking
x^2 + 10x + 13
In my head I have these numbers running round, factors 3, 6 and 5. I know there is a method to working this out like 3 x 13 = 39, and 6 x 5 = 30 etc, but I just can't seem to grasp it?
Any help appreciated
Thanks(Wondering)