- #1
happyparticle
- 431
- 20
- TL;DR Summary
- How to linearized an equation to find the slope
Hi,
First of all, sorry if this is not the right place to post my question I was not sure where exactly to post this kind of question.
I'm wondering how can I find the value of a constant experimentally.
For instance, I have a equation ##l = AB^{4/3}##, with a set of data for ##I## and ##B##.
If the equation above was linear I could find the slope of the graph to get the value for ##A##.
However, this is not a linear equation.
I wondering if I have to linearize the equation and then find the slope to get the value for ##A##?
If so, how exactly I linearize it?
For instance an equation like ##A = BC^{2}e^{-D/C}## could be linearized by multiplying both side by ln, I think.
Thank you
First of all, sorry if this is not the right place to post my question I was not sure where exactly to post this kind of question.
I'm wondering how can I find the value of a constant experimentally.
For instance, I have a equation ##l = AB^{4/3}##, with a set of data for ##I## and ##B##.
If the equation above was linear I could find the slope of the graph to get the value for ##A##.
However, this is not a linear equation.
I wondering if I have to linearize the equation and then find the slope to get the value for ##A##?
If so, how exactly I linearize it?
For instance an equation like ##A = BC^{2}e^{-D/C}## could be linearized by multiplying both side by ln, I think.
Thank you