How to find the y-component of Vi based on a Vy/t graph

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In summary, the conversation discussed the experimental results obtained from a projectile motion ticker tape lab. The individual was asking for help on finding Vy and mentioned that their graph looked strange. They also provided images of a table and graph of Vy to its corresponding time. The conversation also mentioned that the experiment involved measuring the x and y distances of ticker dots and solving for the instantaneous velocity. The individual was then asked to post their original data in a format that could be easily analyzed.
  • #1
devilish_wit
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Homework Statement


These are the experimental results we got from the ticker tape lab we did in projectile motion. How exactly do I find Vy? My graph looks weird. I'm assuming Vy initial must be exactly the first velocity on the table.
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The Attempt at a Solution

 

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  • #2
Please describe the experimental set up and procedure in as much detail as you can. A diagram may help.
 
  • #3
This came from some sort of ticker tape lab, only it’s applied for projectile motion. The papers with the ticker dots were already prepared so we didn’t actually did that experiment. We measured the x and y distance for each dots, then solved for the instantaneous velocity for each time. The images I attached is the table of Vy to its corresponding time, and a graph of Vy/t
 
  • #4
devilish_wit said:
This came from some sort of ticker tape lab, only it’s applied for projectile motion. The papers with the ticker dots were already prepared so we didn’t actually did that experiment. We measured the x and y distance for each dots, then solved for the instantaneous velocity for each time. The images I attached is the table of Vy to its corresponding time, and a graph of Vy/t
Then please post your original data (x, y, t triples, right?), and in a form that readers can cut and paste into a spreadsheet.
 
  • #5
You could do regression analysis to calculate gradient and y-intercept if that's any help ? Possibly leaving out the first two points which don't seem to be part of the 'free fall' data set. Enter t as the x-values and v as the y-values if you want your gradient to show acceleration.
 

FAQ: How to find the y-component of Vi based on a Vy/t graph

How do I interpret a Vy/t graph?

A Vy/t graph plots the vertical velocity (Vy) of an object over time (t). The slope of the graph represents the acceleration of the object, while the y-intercept represents the initial vertical velocity (Vi).

What does the y-component of Vi represent?

The y-component of Vi is the initial vertical velocity of an object at the beginning of its motion. It is the velocity in the y-direction at time t=0.

How do I find the y-component of Vi from a Vy/t graph?

To find the y-component of Vi, simply look at the y-intercept of the graph. This value represents the initial vertical velocity at the beginning of the object's motion.

Can I use a Vy/t graph to find the initial velocity in other directions?

No, a Vy/t graph only shows the velocity in the vertical direction. To find the initial velocity in other directions, you would need to look at other graphs, such as Vx/t or Vz/t graphs, or use vector calculations.

How does the slope of a Vy/t graph relate to the acceleration of an object?

The slope of a Vy/t graph represents the vertical acceleration of an object. A steeper slope indicates a higher acceleration, while a flatter slope indicates a lower acceleration.

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