How to Find Vout/Vin vs. Frequency in a Voltage Divider Circuit

In summary, the conversation deals with finding the response (Vout/Vin) versus frequency for a circuit with a voltage divider composed of an inductor, capacitor, and resistor. The solution involves considering the impedance and reactance of the circuit components, as well as plotting the response versus frequency.
  • #1
phrygian
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Homework Statement



The problem deals with a circuit that has a voltage divider composed of an inductor L and a capacitor C in series connected to a node, one end is an open circuit with the output voltage and the other end is connected to a resistor R that is connected to ground.

Find the response ( Vout/Vin ) versus frequency.


Homework Equations





The Attempt at a Solution




I found the amplitude of V out by finding V out = (Zr / (Zr + Zc + Zl) )*Vin and multiplying V out by its complex conjugate and taking the square root. This got me to |Vout| = R * Vin / ( R^2 + (wL-1/wC)^2)^.5

From that equation I see that V out is 0 at 0 frequency, and then also 0 at infinite frequency but don't know anything about the middle. Am I even on the right track?

Thanks for the help
 
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  • #2
!

Thank you for your post. It seems like you are on the right track with your solution. However, there are a few things that you may want to consider in order to fully answer the question.

Firstly, you have correctly identified that the output voltage, Vout, is dependent on the input voltage, Vin, and the impedances of the circuit components. However, it would be helpful to also consider the phase difference between Vout and Vin, as this will affect the overall response of the circuit.

Secondly, you may want to consider using the concept of reactance, which takes into account the frequency of the input voltage, to simplify your equation. This will give you a better understanding of the behavior of the circuit at different frequencies.

Lastly, it would be helpful to plot the response (Vout/Vin) versus frequency to get a visual representation of the circuit's behavior. This will give you a better understanding of how the output voltage changes with respect to the input voltage at different frequencies.

I hope this helps guide you in the right direction. If you have any further questions or need clarification, please do not hesitate to ask. Good luck with your problem!
 

FAQ: How to Find Vout/Vin vs. Frequency in a Voltage Divider Circuit

1. What is a voltage divider circuit and how does it work?

A voltage divider circuit is a simple electronic circuit that divides a voltage into smaller parts. It consists of two or more resistors connected in series, and the output voltage is taken from the connection between the resistors. The ratio of output voltage to input voltage is determined by the values of the resistors.

2. How do I calculate Vout/Vin in a voltage divider circuit?

The output voltage (Vout) can be calculated by using the formula Vout = (R2 / (R1 + R2)) x Vin, where R1 and R2 are the values of the two resistors in the circuit and Vin is the input voltage.

3. How does the output voltage change with frequency in a voltage divider circuit?

The output voltage in a voltage divider circuit is directly proportional to the input voltage, so it will change at the same rate as the input voltage. However, the output voltage may also be affected by the frequency of the input signal, depending on the values of the resistors and the components in the circuit.

4. How can I plot Vout/Vin vs. frequency in a voltage divider circuit?

To plot Vout/Vin vs. frequency, you will need to measure the output voltage at different frequencies and then plot these values on a graph. You can use a function generator to generate different frequencies and a voltmeter to measure the output voltage. Then, plot the output voltage on the y-axis and the frequency on the x-axis.

5. What factors can affect the accuracy of Vout/Vin vs. frequency in a voltage divider circuit?

Several factors can affect the accuracy of Vout/Vin vs. frequency in a voltage divider circuit. These include the accuracy of the components used, the temperature, and the non-linearity of the components. It is important to use high-quality components and to minimize any external factors that may affect the circuit in order to get more accurate results.

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