- #1
rwooduk
- 762
- 59
1. estimate the fermi energy for lithium... the crystal structure of lithium is a bcc with a unit cell size of 3.5*10^-10 m
i need n, which equals N / V. if i divide by per atom, then i get (N/atom) / (V/atom) = valance / (V/atom). my question is how to get the volume per atom?
bcc's have 2 atoms per unit cell.
volume per atom should be ~10^28 , how do i get this from the unit cell size?
Thanks for any help.
also, not given density etc, just given valance and unit cell size.
i need n, which equals N / V. if i divide by per atom, then i get (N/atom) / (V/atom) = valance / (V/atom). my question is how to get the volume per atom?
bcc's have 2 atoms per unit cell.
volume per atom should be ~10^28 , how do i get this from the unit cell size?
Thanks for any help.
also, not given density etc, just given valance and unit cell size.