How to handle leftover terms in integration after substitution?

In summary, the conversation discusses the integration of \int secx^{3}tanxdx, where u = tanx is substituted and a leftover secx remains. The solution involves differentiating sec(x) = u and seeking help from a PDF on using latex.
  • #1
Triggy
8
0
How do you integrate [tex]\int secx^{3}tanxdx [/tex]

I'm substituting [tex]u = tanx [/tex] so [tex]du = sec^2xdx [/tex]Now the problem is when I made sec^3x into sec^2xsecx then I had a secx left over after my substitution. What do I do with this?

PS: Sorry I'm new at latex and I don't know how to get rid of that {
 
Last edited:
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  • #2
Try sec(x) = u and substituting. When you differentiate this it may become clearer.
 
  • #3
Aahh! Thanks tending to infinity man. I got it.

[tex]\{1/3sec^3x} [\tex]
 
  • #4
Is there like a post on how to use latex?
 
  • #5
Triggy said:
Is there like a post on how to use latex?

If you click on latex images it shows you the code and there is a link below the code to a short PDF with a few tips and small tutorial.

https://www.physicsforums.com/misc/howtolatex.pdf
 
  • #6
Triggy said:
PS: Sorry I'm new at latex and I don't know how to get rid of that {

Delete the \{ and the }.
 
  • #7
Awsome. Thanks Kurdt and GJ
 

FAQ: How to handle leftover terms in integration after substitution?

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