- #1
aj-smith
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I was further looking into the Cauchy schwarz inequality and i got to a statement as follows:
A·B ≤ |A·B|
However, when I tried to prove this using numbers on paper, I wasn't sure if the absolute value bars distribute among each term, which would lead to |A|·|B|, or if the final product is then absolute.
I was wondering how you would interpret the above statement (assuming all capital letters represent vectors
These are the components I assumed.
A= {1,2} B= {-2,3} c= -2
Also how would the following below be interpreted?
|cA·B|
Thank you.
A·B ≤ |A·B|
However, when I tried to prove this using numbers on paper, I wasn't sure if the absolute value bars distribute among each term, which would lead to |A|·|B|, or if the final product is then absolute.
I was wondering how you would interpret the above statement (assuming all capital letters represent vectors
These are the components I assumed.
A= {1,2} B= {-2,3} c= -2
Also how would the following below be interpreted?
|cA·B|
Thank you.