How to interpret the difference in height between two people in this Ames room?

AI Thread Summary
The Ames room creates an optical illusion where two people of different heights appear to be the same height due to manipulated spatial dimensions. The room's design eliminates typical monocular depth cues, leading to misinterpretations of size and distance. Observations about the peculiar alignment of walls and lighting contribute to the confusion regarding the perceived heights of the individuals. The viewer's brain is tricked into assuming a rectangular shape for the room, despite its actual distorted geometry. Understanding the principles of the Ames room can enhance comprehension of visual perception and optical illusions.
zenterix
Messages
774
Reaction score
84
Homework Statement: From a description of the photo below, the woman on the left is actually taller than the boy on the right.
Relevant Equations: This is a so-called "Ames room" and has been constructed to eliminate the usual monocular depth cues that our eyes use to determine distance based on one eye only.

Here is the photo of the room

1729166510452.png


I cannot understand how it can be that she is taller.

In terms of the number of floor tiles, she seems to be just one tile further away from us and each tile is not that long.

There is something weird going on with the wall at the back of the room.

When I look at the lighting on the wall, it looks like the wall behind the woman is behind the wall with the painting and the wall behind the boy is in front of the wall with the painting.

On the other hand, looking at where the walls meet the tiles, it looks like both walls behind the people are in front of the wall behind the painting.

The side walls are also peculiar. It seems like the wall on the left-hand side is taller than the wall on the right-hand side when we look at just the walls. Then again, using the back wall both walls seem to have the same final height.

What gives?
 
Physics news on Phys.org
Are you familiar with Ames rooms?
If not, please see:
https://en.m.wikipedia.org/wiki/Ames_room

If yes, note how the reflections on the floor do not converge towards the observer (you), as in a normal perspective.

The the frame of the picture located on the back wall is not perfectly rectangular, but as your line of vision has been artificially moved to the left, it looks rectangular.
 
  • Like
Likes Motore and Lord Jestocost
zenterix said:
Homework Statement: From a description of the photo below, the woman on the left is actually taller than the boy on the right.
Relevant Equations: This is a so-called "Ames room" and has been constructed to eliminate the usual monocular depth cues that our eyes use to determine distance based on one eye only.

Here is the photo of the room

View attachment 352390

I cannot understand how it can be that she is taller.

In terms of the number of floor tiles, she seems to be just one tile further away from us and each tile is not that long.

There is something weird going on with the wall at the back of the room.

When I look at the lighting on the wall, it looks like the wall behind the woman is behind the wall with the painting and the wall behind the boy is in front of the wall with the painting.

On the other hand, looking at where the walls meet the tiles, it looks like both walls behind the people are in front of the wall behind the painting.

The side walls are also peculiar. It seems like the wall on the left-hand side is taller than the wall on the right-hand side when we look at just the walls. Then again, using the back wall both walls seem to have the same final height.

What gives?
The Ames Room presents the viewer with what appears to be a rectangular room with parallel walls and floors when viewed monocularly from one vantage point. On the homepage of the “Project Lite” from the Boston University you find a DIY “Ames Room Demonstration” under the link “LITE Inkjet Science”: https://www.bu.edu/lite/inkjet-science/index.html
 
zenterix said:
What gives?

There's a fantastic book "Basic Vision: an introduction to visual perception" that has a whole chapter devoted to how our brain extracts 3-D information based on visual cues and provides many examples of optical illusions that exploit this (the Ames room illusion is one).
 
  • Like
Likes PhDeezNutz, Lnewqban and Lord Jestocost
Lnewqban said:
The the frame of the picture located on the back wall is not perfectly rectangular, but as your line of vision has been artificially moved to the left, it looks rectangular.
The viewer's brain assumes everything in the room is rectangular, but nothing in that room is rectangular.
 
  • Like
Likes russ_watters, jbriggs444 and Lnewqban
Thread ''splain this hydrostatic paradox in tiny words'
This is (ostensibly) not a trick shot or video*. The scale was balanced before any blue water was added. 550mL of blue water was added to the left side. only 60mL of water needed to be added to the right side to re-balance the scale. Apparently, the scale will balance when the height of the two columns is equal. The left side of the scale only feels the weight of the column above the lower "tail" of the funnel (i.e. 60mL). So where does the weight of the remaining (550-60=) 490mL go...
Consider an extremely long and perfectly calibrated scale. A car with a mass of 1000 kg is placed on it, and the scale registers this weight accurately. Now, suppose the car begins to move, reaching very high speeds. Neglecting air resistance and rolling friction, if the car attains, for example, a velocity of 500 km/h, will the scale still indicate a weight corresponding to 1000 kg, or will the measured value decrease as a result of the motion? In a second scenario, imagine a person with a...
Scalar and vector potentials in Coulomb gauge Assume Coulomb gauge so that $$\nabla \cdot \mathbf{A}=0.\tag{1}$$ The scalar potential ##\phi## is described by Poisson's equation $$\nabla^2 \phi = -\frac{\rho}{\varepsilon_0}\tag{2}$$ which has the instantaneous general solution given by $$\phi(\mathbf{r},t)=\frac{1}{4\pi\varepsilon_0}\int \frac{\rho(\mathbf{r}',t)}{|\mathbf{r}-\mathbf{r}'|}d^3r'.\tag{3}$$ In Coulomb gauge the vector potential ##\mathbf{A}## is given by...

Similar threads

Replies
5
Views
2K
2
Replies
52
Views
7K
Replies
2
Views
2K
Replies
6
Views
4K
Replies
1
Views
3K
Replies
1
Views
3K
Back
Top