How to intuitively think of translations and Galilean boosts commuting?

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binbagsss
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how to think of translations and Galilean boosts commuting intuitively
 
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How fast something is going and in what direction doesn't depend on where you are.
 
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  • #3
Depends on your definition of intuitive, but if a translation is T(X) = X + A and a boost is B(X) = X + Vt, then TB(X) = BT(X) = X + Vt + A because addition commutes.
 
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Moderator's note: Thread moved to the Classical Physics forum since that is the proper context for discussion of Galilean boosts.
 
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binbagsss said:
translations
Note that this has to mean spatial translations for your statement in the OP to be true. Galilean boosts and time translations do not commute.
 
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  • #6
One builds intuition by working through problems. There is no magic trick to it.
 
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Imagine yourself in a car. You press accelerator pedal (this is boost), then you wait for some time (=time translation). Obviously, after these two transformations you'll find yourself far from the place you've started from.

In reverse order: You wait for some time (=time translation), then you step on accelerator (=boost). You have not moved.

Conclusion: time translations and boosts do not commute.
Eugene.
 
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meopemuk said:
press accelerator pedal (this is boost)

How?
 
  • #10
By definition, boost is a transformation that changes velocity of reference frame.

When I press accelerator pedal, velocity of my car changes. Then the inertial reference frame associated with me and my car experiences a boost.

Eugene.
 
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meopemuk said:
By definition, boost is a transformation that changes velocity of reference frame.

When I press accelerator pedal, velocity of my car changes. Then the inertial reference frame associated with me and my car experiences a boost.

Eugene.
During the acceleration itself you're not experiencing what physicists would call a 'boost'. Inertial observers are connected by 'boosts'. During acceleration you're not an inertial observer.
 
  • #12
meopemuk said:
By definition, boost is a transformation that changes velocity of reference frame.

No, boost changes inertial reference frame to a different inertial one.
 
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  • #13
weirdoguy said:
No, boost changes inertial reference frame to a different inertial one.
True, during acceleration I am not an inertial observer. But after I released the accelerator pedal, I move with a constant speed and I may regard myself as an inertial observer, which is boosted with respect to my previous state.

I agree that this is not a perfect analogy for boost, but not a bad one if we disregard the (short) time during which I am stepping on the gas pedal.

Perhaps, a better analogy would be to jump (mentally) to another car that passes nearby.

Eugene.
 
  • #14
haushofer said:
Actually, they don't commute in the Bargmann algebra :P See e.g.

https://arxiv.org/abs/1011.1145
From the abstract I see the Bargmann algebra is assoicated with the centrally extended Galilean algebra. Could you give, very briefly, implications of what this means compared to the question I asked which was on, what I assume can be referred to as the unextended Galilean group. thanks
 
  • #15
PeterDonis said:
Note that this has to mean spatial translations for your statement in the OP to be true. Galilean boosts and time translations do not commute.
ofc.
 
  • #16
meopemuk said:
True, during acceleration I am not an inertial observer. But after I released the accelerator pedal, I move with a constant speed and I may regard myself as an inertial observer, which is boosted with respect to my previous state.

I agree that this is not a perfect analogy for boost, but not a bad one if we disregard the (short) time during which I am stepping on the gas pedal.

Perhaps, a better analogy would be to jump (mentally) to another car that passes nearby.

Eugene.
A reference frame is not an object like a car that has a single trajectory. A boost is not a physical process like acceleration of an object. A boost is a mapping or transformation from one reference frame to another.
 

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