How to Modify Vector Elements to Double Values Less Than a Minimum?

  • MHB
  • Thread starter needOfHelpCMath
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In summary, we have a conversation about how to double the value of any element in an array that is less than a given minimum value. The solution involves using a for loop and an if statement to check each element and double it if it is smaller than the minimum value. The code provided in the conversation only doubles all elements in the array, but a corrected solution would only double the elements that meet the given condition.
  • #1
needOfHelpCMath
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I don't understand how it able to skip one element to the other in order to multiply the numbers by 2. It be helpful if anyone can explain.Double any element's value that is less than minVal. Ex: If minVal = 10, then dataPoints = {2, 12, 9, 20} becomes {4, 12, 18, 20}.
Code:
#include <iostream>
#include <vector>
using namespace std;

int main() {
   const int NUM_POINTS = 4;
   vector<int> dataPoints(NUM_POINTS);
   int minVal = 0;
   int i = 0;

   dataPoints.at(0) = 2;
   dataPoints.at(1) = 12;
   dataPoints.at(2) = 9;
   dataPoints.at(3) = 20;

   minVal = 10;

   /* Your solution goes here  */
  for(i = 0; i < NUM_POINTS; ++i) {
   dataPoints.at(i)= dataPoints.at(i) * 2;
  }
 
   for (i = 0; i < NUM_POINTS; ++i) {
      cout << dataPoints.at(i) << " " ;
   }
   cout << endl;

   return 0;
}
✖ Testing minVal = 10 and dataPoints = {2, 12, 9, 20}
Expected output: 4 12 18 20
Your output: 4 24 18 40
Tests aborted.
 
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  • #2
You are simply doubling all elements of the array...inside the for loop you need to use an if statement to check if the element is less than [M]minVal[/M], and only if it is, then double the element. :)
 
  • #3
MarkFL said:
You are simply doubling all elements of the array...inside the for loop you need to use an if statement to check if the element is less than [M]minVal[/M], and only if it is, then double the element. :)

i was only able get the first element to be multiply.
Code:
if (i < minVal) {
      dataPoints.at(i) = dataPoints.at(i) * 2;
   }
   else {
      dataPoints.at(i) = i;
   }

   for (i = 0; i < NUM_POINTS; ++i) {
      cout << dataPoints.at(i) << " " ;
   }
   cout << endl;

   return 0;
}
Testing minVal = 10 and dataPoints = {2, 12, 9, 20}
Expected output: 4 12 18 20
Your output: 4 12 9 20
Tests aborted.
 
  • #4
You need to use the array element, not the loop index for the comparison. Like so:

Code:
for(i = 0; i < NUM_POINTS; i++)
{
	if (dataPoints.at(i) < minVal)
	{
		dataPoints.at(i) *= 2;
	}
}
 

FAQ: How to Modify Vector Elements to Double Values Less Than a Minimum?

How can I modify a specific element in a vector?

To modify a specific element in a vector, you can use the index operator [ ] and specify the index of the element you want to modify. For example, if you want to modify the third element in a vector named myVector, you can use myVector[2] = newValue, where newValue is the new value you want to assign to that element.

Can I modify multiple elements in a vector at once?

Yes, you can modify multiple elements in a vector at once by using the range-based for loop or the std::for_each() function. Both methods allow you to iterate through the vector and modify each element as you go.

How do I insert a new element into a vector?

To insert a new element into a vector, you can use the .insert() function and specify the position where you want to insert the element, along with the value of the element you want to insert. Alternatively, you can use the .push_back() function to insert the element at the end of the vector.

What happens when I modify a vector's element that is out of range?

If you try to modify a vector's element that is out of range, your program may crash or produce unexpected results. It is important to make sure that the index you are using to modify the element is within the bounds of the vector's size. You can use the .size() function to check the size of the vector before modifying any elements.

Can I modify a vector's elements without changing its size?

Yes, you can modify a vector's elements without changing its size by using the .at() function instead of the index operator [ ]. The .at() function performs bounds checking and will throw an out_of_range exception if you try to access an element that is out of range. This can help prevent your program from crashing if you accidentally try to modify an element outside of the vector's size.

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