- #1
Voehet
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How would I go about proving that the argument below is valid using the induction method?
(∃x)[P(x)!Q(x)]^(∀y)[Q(y)!R(y)]^(∀x)P(x)!(∃x)R(x)
Thank you very much in advance!
(∃x)[P(x)!Q(x)]^(∀y)[Q(y)!R(y)]^(∀x)P(x)!(∃x)R(x)
Thank you very much in advance!