- #1
Albert1
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The measurement of each side length of a heptagon $ABCDEFG$ is equal to 1,
the diagonal of $\overline{AD}=a,$ and the diagonal of $\overline{BG}=b \,\,(a>b)$
prove :$(a+b)^2(a-b)=ab^2$
the diagonal of $\overline{AD}=a,$ and the diagonal of $\overline{BG}=b \,\,(a>b)$
prove :$(a+b)^2(a-b)=ab^2$