- #1
thelegend09
- 1
- 0
Fourier series summation...help!
Basically, i need to show that...
2 + sum (m=1 to n) [4(-1)^m . cos(m.pi.x)] = 2(-1)^n.cos((n+1/2)pi.x)/cos((pi.x)/2)
Any ideas?
Basically, i need to show that...
2 + sum (m=1 to n) [4(-1)^m . cos(m.pi.x)] = 2(-1)^n.cos((n+1/2)pi.x)/cos((pi.x)/2)
Any ideas?