How to Relate Formulas for Calculating Force Between Charges

  • Thread starter chemboy
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In summary, the conversation discusses the relationship between distance, net charge, and force between two charges. It is mentioned that when the distance between the charges is doubled, the effect on net charge is 0.25 of the original force, and the force is increased by 6 times. The participants also consider the formulas Fe = 1/r^2 and Fe = q1q2/r^2 to mathematically show this relationship. The concept of proportion is highlighted as a method to solve any formula and the speaker expresses concern over the mathematical aspect of the problem.
  • #1
chemboy
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if the following takes place simultaneously

distance betwen two charges is doubled and one charge is doubled and the other is trippled how do I set this up mathmatically

I understand that when distance doubles (r) then the effect on net charge is .25 of original F
also
I understand that the force betwen charges when increased as mentioned above, there will the force will increase by 6X

Im thinking simply the answer is 6X the force X .25 but there must be a way to relate the formulas Fe = 1/r^2 and Fe = q1q2/r^2 to show this

If I knew what r was then I could use Fe = kq1q2/r^2

Im worried this is a mathmatical problem and not that I don't understand the theory behind the physics.

any help??

will it end up something like

F = (9.0 X 10^9N*m^2/C^2) X 6(6.0X10^-8 N) / 4
 
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  • #2
Consider this:

if a=2b and c=4b then what mathematical operation does one have to do to know how many times c is larger than a?
 
  • #3
Hi chemboy! :smile:
chemboy said:
I understand that when distance doubles (r) then the effect on net charge is .25 of original F
also
I understand that the force betwen charges when increased as mentioned above, there will the force will increase by 6X

Im thinking simply the answer is 6X the force X .25 but there must be a way to relate the formulas Fe = 1/r^2 and Fe = q1q2/r^2 to show this

Yes … that's completely correct! :smile:

You looked at the formula q1q2/r², and you correctly said "it's proportional to q1 and to q2, and inversely proportional to the square of r … so it's 2 x 3 / 4".

This "proportion" method works for any formula! :biggrin:

Why are you worried? :confused:
 

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